Unless I misunderstood what you tried to say ... I thought linear with current.
Nope. Well, linear is probably the wrong term. Proportional is correct. The output of an ideal driver in dB would be directly proportional to the output in db Volts of an amplifier.
That is, if you increase the V by 3 dB, you should measure 3 dB more acoustically regardless of the final speaker impedance (i.e. drivers + crossover).
Of course most speakers are not ideal and compression artifacts occur but this is the goal so long as we are not overdriving the speaker.
This is also why equalizers work. :) If you reduce output by 6 dB at 40 Hz in your EQ then your speaker’s output will be reduced exactly that much. Because everything is proportional to voltage.
PS, db Volts is calculated this way:
db = 20 x log( V original / Voltage now)
So doubling the amplifier voltage = 6 dB louder in both voltage and sound pressure level (SPL) so long as everything is not over driven.