Why ARC featured such function in their reference phono stage that serve no purpose? So they can charge more?🤔
We have a loading strip on our preamps too, and I advise customers with LOMC cartridges to not use it. But if you have a higher output cartridge, the loading strip can be quite handy! Because of their higher inductance, high output cartridges have that electrical peak at a lower frequency, which can be at the high end of the audio band or just outside of it. The winding of a higher output cartridge tends to have a lower Q value so loading can be helpful to reduce ringing.
" The industry spec is 47K for all cartridges. " where is the " official " announcement about, say by the AES that coul confirm it? where?
Cripes. If one is grounded in audio history then this is obvious. ARC SP6: 47K phono input impedance; similarly H/K Citation 1, Marantz 7, Conrad Johnson PV12, etc., etc.
" less able to trace high frequencies. " again: where are the white papers that can confirm it.
It has to be published to be real?? Since JCarr published something, you're not challenging his statement (despite the obviously recursive aspect of that argument...), you're employing a double standard. In order for the cantilever to not get stiffer a fundamental rule of physics (law of energy conservation https://energyeducation.ca/encyclopedia/Law_of_conservation_of_energy) has to be violated. IOW you would have free energy and the world's energy issues would be solved 😂
So no papers needed- just a grounding in basic physics (high school level), in particular how alternators and generators work. A 'Sheesh!' is in order here.
That is ridiculous and with no facts or diagrams/equations that shows exactly that. I That " can easily get you outside of this target window ( ideal resonance frequency range. ) " is not proved here or in any other subject threads. Again: only IMAGINATION.
Ohm's Law and the power formulas are not a figment of someone's imagination 😁
The cartridge is being asked to do just under 2 1/2 orders of magnitude more work with the example you provided:
47,000/100 = 470
-meaning 470X more current is drawn from the cartridge; because 47K is so high a resistance value relative to the impedance of the cartridge winding, the output voltage is essentially unaffected so the current increase also represents the wattage increase).
Anyone with an elementary school education can work out the math here. Perhaps, knowing that, you can tell me where that current is coming from?? If you can answer that, a bonus question: what is the consequence of that current flow?
This is such simple math I don't see why a paper needs to be written about it, but maybe even though its basic, some people simply haven't thought it thru. Or didn't do so well in math.
Please do answer the questions.
