... your illustration only shows a 5 amp current draw on a 20 amp circuit breaker, there in not any way 5 amps could trip a normal 20 amp circuit breaker.Yes, and that’s exactly the problem, as page 29 of the reference very clearly explains. In the event that a fault in a component causes the AC line voltage to come in contact with the metal chassis of the component the breaker is supposed to trip to prevent the possibility of someone being shocked or electrocuted. But with the grounding configuration described by you and on page 29 of the reference the breaker will not trip, leaving the chassis of the component energized at 120 volts (or whatever the line voltage is in the particular country). Thus defeating the fundamental purpose of the safety ground wiring.
If however there was a 5 amp short like in the page 29 schematic there is no reason that it would not be safely discharged to ground.
It would be discharged to ground, but not safely because the chassis of the component would continue to be electrified at the full AC line voltage. I’m not sure how that can be explained any more clearly than it is on page 29 of the reference.
Regards,
-- Al