Duelund DCA16GA

Does the tin coating on this wire melt away during soldering when making ICs?

For those of you who use bare ends for speaker cable, are you removing the tin coating with something like Scotch-Brite? It doesn’t seem like a very good idea for the signal to have to pass through the tin coating.

I’m debating making a set of speaker cables for my Magnepan 3.6Rs that are bi-wireable. How many runs and what configuration would work? The amplifier is a Classe CA-200 and the they will be 7 to 8 feet long. Would non-biwiring work better?

I thought the dielectric was responsible for the sound of this wire?  The tin coating is to prevent oxidation.

No, it does not melt off and cannot be removed

I'm not proposing to remove all of the tin coating, just the very end were it gets soldered.  It should be very easy to get off with Scotch-Brite, right?  It should just be a very thin layer.  Copper is a much better conductor than tin.  If you remove the tin, the signal will travel from the copper in the wire to solder to the RCA connector instead of from the copper of the conductor, through the tin, through solder, and finally to the RCA connector.  It's one less layer of a (poor) conductor that the signal has to pass through.
Have you compared cables with and without the tin removed?