Power conditioner vs use of a audio grade outlet?

@erik_squires  , okay, thanks, I must have misunderstood something on that previous thread.  I'll try to find it later & maybe paste the link to it for you?

@erik_squires  , the pictured outlet is a 15A outlet?  Which would require a 15A breaker?

@erik_squires  you will not get any argument from me re NEC.  I am totally learning.  It was just that I participated in a thread not all that long ago, ad to make the long story shorter, I was saying that I had 20A outlets and 12-2 and I was protecting them with a 15A breaker as I thought that would be safer.  I was told that the breaker itself was what determined the circuit, and although I might be right that having the lower amperage breaker to be on the safe side of tripping, to be compliant my breaker and outlet should match.  At least that was the way I interpreted the advice I was getting. 

@erik_squires  , it took a while, but I think I have finally comprehended the 15A/20A outlet subject.

But

Oh dear dark goddess of the undworld..... no!! 🤣

@vaejoviscarolinanus

The correct thing to do is to use a GFCI outlet OR to have an electrician properly install a grounding electrode and bond it to the neutral at the service entrance. THEN and only then you run a ground to your outlets.

You don’t run a separate ground, and you sure as hell don’t tie your ground to the neutral anywhere else.

for my continuing education only, NOT because I was ever considering doing this, could you explain for me why a separate ground is prohibited?  Again, this is strictly for my education on the subject.  Thank you.

@erik_squires  , thank you for the explanation. 

@erik_squires  , on the same subject, what is it that happens to the voltage carried by the white neutral wire when it reaches the neutral/ground bar in the electrical panel that makes it no longer dangerous?

Thank you for sticking with me on this, @erik_squires  , if you could bear with me just a bit longer:

if this was the ideal circuit in a utopian world of circuitry and there was NO resistance

(V=5A x 0R=0V)

then you are saying that although 5 amps of current are flowing through this white neutral wire, it is not dangerous because the formula dictates that 0 volts are created.  In this hypothetical circuit.  Correct?

But you are also saying that in reality this hypothetical circuit doesn't exist, and the example you used of what does exist is

v=5Ax10R=50V

so the white wire (with 10R) is not only carrying current, but because of the 10R it is also carrying volts?  Is that correct?

(And on an aside, doesn't this mean that the old saying, "it's not the volts but the amps that kills you" is not exactly correct, as I am getting out of this that amps without R would not be dangerous?)

But back to my question that prompted this explanation from you: in the real world circuit that you used for an example

V=5Ax10R=50V

what happens to that formula when it reaches the neutral bar via the white wire?  Is it that because of the massive ground cable that ALL resistance disappears at this point and the ingredients for the 50V are gone?

Thank you, @erik_squires  .