How much lead/sand to fill stand rack?


Hi,
I have a Atlantis Ref speaker stand 24" tall, 4 collums with 4"x4" for each collum. So, if I fill up 2/3 for each collum with lead shot, it'll take me 12 bags of lead shot (25lbs/bag) for one stand. However, if I mix lead with silica sand, it'll take me 2 1/2 bags of lead with 15lbs of sand for each stand. I did it yesterday, and my speaker stand now weight over 100lbs/stand. It's so heavy for me to move now because I weight only 120lbs. My question is the more heavier the stand the better? Do I really need to fill up 2/3 of the height of the stand like people suggesting? What the sound will be like if I fill up 1/3 or 1/2 of the collum's height? Please help
Thank you very much
DT
worldcup86

Showing 1 response by dem

This may not be worth the trouble (it may not be easily done with larger stands like yours), but I have filled several smaller diameter metal speaker stands with sand/lead in this way. If you strike a medium sized tuning fork and place it in contact with a short length of metal tube (1"to 2" diameter) containing 2 to 3 inches of sand, you should notice the sand furioulsy vibrating/moving in reaction to the tuning fork. This shallow depth of sand allows for this movement, which transforms this energy into heat. If the sand depth is too deep, I have observed less movement in the sand, likely due to the larger mass and settling of the sand. To maintain this type of energy transfer, I have layered sand, with small "spacers" made of high-density foam-rubber, so that each layer of sand has a small amount of space between layers. This allows each pocket of sand to vibrate more freely. Also, I place an amount of lead shot in the bottom of the stands for stability. I also use this construction method, i.e., partially filled layers of honeycombed "pockets of sand" in my home-made amp and sub-woofer stands, which works better than mass-loading alone in my trials. Good Luck.