If edge supposed to reflect infrared then it should be gold marker, but if it supposed to kill reflections it should be black. Green doesn't make sense.
What's the deal with coloring CD's and/or tray mechanism
I just stumbled across an old thread discussing this process, and the sonic advantages. It's intriguing, and I wonder what other members think. I am primarily into vinyl, and don't listen to cd's that often, but if I can improve the audio quality, then I am interested, to say the least.
I am concerned though, about painting the tray of my McIntosh, for fear of damage, and also de-valuing it's re-sale value
Showing 7 responses by kijanki
Black absorbs all wavelengths. Special infrared sinking paints, used by military, are all black matte. Cheap version, often used, is Krylon 1602. You can easily test it with infrared led (remote control etc) and cellphone (since they show infrared as visible light). Thin layer of water would be completely useless. |
Geoffkait, pure matte black has 100% absorption of all colors. Other colors are used only to reflect only one color. Targets for infrared, for counting number of pulses in rotational speed measurements, are usually gold/matte black (including one I designed: http://himmelstein.com/images/product-datasheets/0807545dc201B8701.pdf ) As I mentioned before you can see infrared with your phone camera and test it for yourself. |
As I said you can see for yourself with a red laser poster how much is reflected off the black tray.nalso, of the black matte tray was actually 100% effective the green pen wouldn’t make any difference. It doesn't, according to many. You are trying to make up theory based on some silly tweak, that according to many doesn't work at all. the reason you see the infrared is because it’s near infrared next to the visible part of the spectrum thus part of the signal is in the red zone.No, spectrum of the infrared emitting diode is very narrow and it does not project white light. You still cannot see it with naked eye. The portion that you can see if you look directly into transmitter will be dark red. The reason camera can see it is because camera sensors are sensitive to infrared up to around 1100nm. You see white light because red green and blue sensor filters are not very strong and all of them pass some infrared. "Other colors are used only to reflect only one color."You still don't get it. Perhaps this drawing will help you: http://archive.cnx.org/resources/b3c8a8818e60b70ff638c267249826b1e5c0747f/Figure_27_03_02.jpg |
As I explained earlier - spilled light would appear as mostly red but it shows as white (no red at all), because all camera sensors can see infrared and filters are not able to filter it completely. If you cannot understand it I cannot help it. Also LED transmitters have narrow band, like this one: http://www.vishay.com/docs/81009/tsal6100.pdf As you can see there is no light emitted below 840nm (Fig. 8) while visible light ends at 750nm. If you compare two cameras one with the film and another with digital sensor set to the same sensitivity you’ll find that infrared won’t be visible on the picture made with film camera but will show as white light on the one with digital sensor. It is not because of "spilled" light but because digital sensor is sensitive to infrared and film isn’t. I’m not sure if your understanding of this is as poor as one of the class D amps, but it is getting close. No sense to discuss it any further. |