i like 10k-ish region of impedance for benz.

if you don't have any array of resistances first open the box and see if someone already soldered load resistances and determine a value.

you can order this array from partsconnexion.com(Caddock) that have a great reputation and provide a great and fast service all arround the world. They prefere accepting orders through the phone. Their phone is on their web page.

i'd figure that you have an originally installed 47k (for MM)resistors at phono input and all you should do is to determine a resistor that you want to plug-in.

If you go with 10k resistor your resulting load resistance will be approximately 9k but if you go with another 47k resistor your resulting load resistance will be 28.5k.

follow the formula of two resistors connected in-parallel:

Ro = 47k*Rs\46k+Rs

Where Ro is resulting resistance and Rs is the one you select for your experiment.

If you realy want to test by-ears you should arrange a bread-board and thread-out an aligator clips or test plugs so you can change the load resistance on-the-flight.

FYI

Please note that resulting resistance of two resistors in parallel will result smaller resistance of the smallest among two. If one resistance is infinitessimally small and another resistance is infinitessimally large in comparison to each other than you can approximate the result resistance simply by the smallest one. For example you can easily assume that if you will need to load only with 50 Ohms having 47k resistor in-parallel than you can simply assume that by applying 50Ohm resistor you will get almost 50Ohm.

if you don't have any array of resistances first open the box and see if someone already soldered load resistances and determine a value.

you can order this array from partsconnexion.com(Caddock) that have a great reputation and provide a great and fast service all arround the world. They prefere accepting orders through the phone. Their phone is on their web page.

i'd figure that you have an originally installed 47k (for MM)resistors at phono input and all you should do is to determine a resistor that you want to plug-in.

If you go with 10k resistor your resulting load resistance will be approximately 9k but if you go with another 47k resistor your resulting load resistance will be 28.5k.

follow the formula of two resistors connected in-parallel:

Ro = 47k*Rs\46k+Rs

Where Ro is resulting resistance and Rs is the one you select for your experiment.

If you realy want to test by-ears you should arrange a bread-board and thread-out an aligator clips or test plugs so you can change the load resistance on-the-flight.

FYI

Please note that resulting resistance of two resistors in parallel will result smaller resistance of the smallest among two. If one resistance is infinitessimally small and another resistance is infinitessimally large in comparison to each other than you can approximate the result resistance simply by the smallest one. For example you can easily assume that if you will need to load only with 50 Ohms having 47k resistor in-parallel than you can simply assume that by applying 50Ohm resistor you will get almost 50Ohm.