Need help with high pass filter


Does anybody have a formula to figure out the right uF for a capacitor and k-ohm for resistor (ground) to make a130Hz high pass filter between pre-amp and poweramp with an imput impeadance of 33 kohms? Your help would be greatly appreciated!!
arni

Showing 2 responses by joegio

Well I'm not sure about the resistor unless its to create a filter of a higher order. Anyway I took one of the Vandersteen filters apart and found two caps in parallel which sum the capacitance, but no resistor. If the resistor is in series than I think you would add it to the capacitive impedance, if in paralel than its 1/Z = 1/Xc + 1/Xr where Xc is capacative reactance and Xr is resistance reactance. This is where a spreadsheet comes in handy. Again I'm no expert, but I think this is how it goes.
Well here is my guess since impedance for a cap is 1/wc where w =2*PI*f where f is the frequency in Hz. looks like 33,000= 1/(2*PI*130*c) or c= 1/(2*PI*130*33,000) * 1,000,000 in uF = .0362uF How did I do guys (gals) ?