voltage gain = inverse log (dB gain / 20)

inverse log X is 10 raised to the power of X

You are looking to make up the difference of 15dB from the 80dB MC stage to the 65dB MM stage.

15dB divided by 20 = .75

take the inverse log of .75 = 5.6

.3 mV times 5.6 = 1.7 mV

So .3 mV amplified 80dB will have the same output as 1.7 mV amplified 65dB.

80dB is a gain of 10,000. So 10,000 times .3 mV = 3V

65dB is a gain of 1,778.. So 1,778 times 1.7 mV = 3V

inverse log X is 10 raised to the power of X

You are looking to make up the difference of 15dB from the 80dB MC stage to the 65dB MM stage.

15dB divided by 20 = .75

take the inverse log of .75 = 5.6

.3 mV times 5.6 = 1.7 mV

So .3 mV amplified 80dB will have the same output as 1.7 mV amplified 65dB.

80dB is a gain of 10,000. So 10,000 times .3 mV = 3V

65dB is a gain of 1,778.. So 1,778 times 1.7 mV = 3V