bypassing a crossover in a two-way


i am not a tech person so forgive any ignorance. i want to bypass the crossover in a simple and cheap two way, because the main driver is the same one used in the manufacturer's crossoverless design.

the manufacturer gave me the following instructions: "A 0.68uf cap in series with the tweeter + lead is all you need,, - to the - binding post." I'm not sure what this means. looking into the speaker i can see the black and red wires leave the speaker leads and inter the crossover network. leaving the crossover are two sets of black and white wires, one set going to the leads on the woofer, the other connected to the single wire from the tweeter.

am i to cut the speaker wire before it reaches the crossover and then insert the cap? if so, how, specifically, do i these three connections to a single cap (1. the input from the speaker leads, 2. the output to the woofer, and 3. the output to the tweeter)? i am not able to visualize his statement in relation to what i've described as the inside the speaker cabinet. i've looked elsewhere on the web but to no avail. i realize it is simple but just don't have the background.

any help would be very much appreciated.
thomp9015

Showing 2 responses by eldartford

Thomp9015...Suggestion...Modify one speaker and compare it with the other unmodified one. Another idea...Just add a shorting wire across the inductor that is in series with the woofer, with a switch in it. Now you can make comparisons just by playing with the switch.
Why, Why, Why??? The manufacturer gave you a crossover because, above the XO frequency the woofer doesn't work as well as the tweeter. Cone drivers typically have lumpy frequency response in a range before they roll off, and you really want to turn them off before that happens.