Yes. If the gain of the two amps is not the same, you'll have to insert an attenuator into the path of the amp with the larger gain. You want the voltage levels at the speaker posts to match.
9 responses Add your response
Gain, unbalanced input: 28.7x, 29.5dB (with input switch set to 1V)
Output noise, 8-ohm load, unbalanced input, 1k-ohm input termination: wideband 0.260mV, -80.7dBW; A weighted 0.067mV, -92.5dBW.
Output noise, 8-ohm load, balanced input, 600-ohm input termination: wideband 0.307mV, -79.3dBW; A weighted 0.083mV, -90.6dBW.
(balanced inputs) CA-2200
voltage gain 29.1dB
Are these gains close enough?
Sashav, why does the input sensitivity have to match? I can see if they are wildly different one amp would reach its max power way before the other, but I don't understand why they have to match. My understanding is that for a given input voltage we want to have the same output voltage for each amp, so gain is the only determinant.
This is exactly what I thought, I was beating this question to death on various forums, was getting different opinions, and finally tried it myself.
Had two amps of exactly the same gain, one of them was also 4B SST with 29db gain in 1V position, but different sensitivity (the other was 0.7V).
I tried various combinations (the one with 0.7V driving MF/HF, or just HF), no matter what I tried the one with 0.7V always produced noticeably higher level of frequencies it was driving.